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Four particles each of mass m are placed...

Four particles each of mass `m` are placed at the corners of a square of side length `l`. The radius of gyration of the system about an axis perpendicular to the plane of square and passing through its centre is

A

`l/(sqrt(2))`

B

`l/2`

C

`l`

D

`sqrt(2)l`

Text Solution

Verified by Experts

The correct Answer is:
A
` I = Sigma mr^(2) = 4m [l/(sqrt(2))] ^(2) = 2ml^(2)`
` :. ` Radius of gyration
` K = sqrt(I/(M)) = sqrt((2ml^(2))/(4m) ) = l/(sqrt(2))`
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