A uniform rod of mass m is bent into the form of a semicircle of radius R. The moment of inertia of the rod about an axis passing through A and perpendicular to the plane of the paper is

Options

A. `(ml^(2))/2 `
B. `2ml^(2)`
C. `(ml^(2))/(pi^(2))`
D. `(2ml^(2))/(pi^(2))`

Answer

D

Explanation

`r = l/A , I = 2mr^(2)`