A mass is whirled in a circular path wit...

A mass is whirled in a circular path with a constant angular velocity and its angular momentum is L. If the string is now halved keeping the angular velocity same, the angular momentum is

L/2

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The correct Answer is:

` L = mr^(2) omega rArr L prop r^(2)`
` :. L_(2) = L_(1) xx ((r_(2))/(r_(1)))^(2) = L/4`

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