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If three particles of masses `2kg, 1kg` and `3kg` are placed at corners of an equilateral triangle of perimeter `6m` then the distance of centre of mass which is at origin of particles from `1kg` mass is (approximately) (Assume `2kg` on x-axis)

A

`sqrt(6)m`

B

`sqrt(2)`m

C

`1/(sqrt(2))m`

D

`2m`

Text Solution

Verified by Experts

The correct Answer is:
B

Coordinates of 1 kg , 2 kg , 3 kg are (0,0) (2,0) `(1 ,sqrt(3))` respectively `X_(cm) = (Sigmam_(i)x_(i))/(Sigmam_(i))`
`Y_(cm) = (Sigmam_iy_(i))/(Sigmam_(i)) , r _(cm) = sqrt(X_(cm)^(2) +Y_(cm)^(2))`
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