A body of mass `m` is dropped and another body of mass `M` is projected vertically up with speed `u` simultaneously from the top of a tower of height `H`. If the body reaches the highest piont before the dropped body reaches the ground, then maximum height raised by the centre of mass of the system from ground is

Options

A. `H+(u^(2))/(2g)`
B. `(u^(2))/(2g)`
C. `H + 1/(2g) ((Mu)/(m+M))^(2)`
D. ` H + 1/(2g) (("mu")/(m+M))^(2)`

Answer

C

Explanation

`h_(max) = H + ((u_(cm))^(2))/(2g)`