The angular frequency of a fan of moment...

The angular frequency of a fan of moment of inertia `0.1kgm^2` is increased from 30rpm to 60rpm when a torque of `0.03Nm` acts on it. The number of revolutions made by the fan while the angular frequency is increased from 30rpm to 60rpm

`7.855` rev

`6.855`rev

`5.855` rev

`8.855` rev

Text Solution

Verified by Experts

The correct Answer is:

`tau = I alpha , omega^(2) - omega_(0)^(2) = 2alpha theta , theta = 2pi N `

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