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Three identical particles each of mass `0.1 kg` are arranged at three corners of a square of side `sqrt(2) m`. The distance of the centre of mass from the fourth corners is

A

2/3m

B

4/3m

C

1m

D

8/3m

Text Solution

Verified by Experts

The correct Answer is:
B

`r_(cm)=sqrt(x_(cm)^(2)+y_(cm)^(2))`
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