Two particles of masses `2kg` and `3kg` are projected horizontally in opposite directions from the top of a tower of height `39.2m` with velocities `5m//s` and `10m//s` respectively. The horizontal range of the centre of mass of two particles is

Options

A. `8sqrt(2)` m in the direction of 2 kg
B. `8sqrt(2)` m in the direction of 3 kg
C. `sqrt(8)` m in the direction of 2 kg
D. `sqrt(8)` m in the direction of 3 kg

Answer

B

Explanation

Range of C.M = `v_(cm)sqrt((2h)/g)`
But `v_(cm) = (m_(1)v_(1)+m_(2)v_(2))/(m_(1)+m_(2))`