The mass of a thin circular plate is `M` and its radius is `R`. About an axis in the plane of plate at a perpendicular distance `R//2` from centre of plate, its moment of inertia is

Options

A. `(MR^(2))/4`
B. `(MR^(2))/2`
C. `(3MR^(2))/4`
D. `(3MR^(2))/2 `

Answer

B

Explanation

` I = I_(c ) + Md^(2) = (MR^(2))/4 + M (R/2)^(2)`