The moment of inertia of a solid cylinde...

The moment of inertia of a solid cylinder about its natural axis is `I`. If its moment of inertia about an axis `bot^r` to natural axis of cylinder and passing through one end of cylinder is `19I//6` then the ratio of radius of cylinder and its length is

`1:2`

`1:3`

`1:4`

`2:3`

Text Solution

Verified by Experts

The correct Answer is:

` I =(MR^(2))/(2) , I_(1) = (19I)/6 = (ML^(2))/3 + (MR^(2))/4 `

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