The moment of inertia of a wheel of radi...

The moment of inertia of a wheel of radius `20 cm` is `40 kgm^(2)` if a tangential force of `80 N` applied on the wheel, its rotational `K.E.` after `4s` is

16.2 J

51.2 J

25.6 J

24.8 J

Text Solution

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The correct Answer is:

`omega = omega_(0) + alphat . KE = 1/2 Iomega^(2)`

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