An initial momentum is imparted to a homogenous cylinder, as a results of which it begins to roll without slipping up an inclined plane at a speed of `v_(0)=4m//sec` the plane make an angle `theta=30^(@)` with the horizontal. What height `h` will be the cylinder rise to? `(g=10 m//s^(2))`

Options

A. `0.8` m
B. `1.2` m
C. `1.0`m
D. `1.6`m

Answer

B

Explanation

` a =(g sin theta )/(1+(K^(2))/(R^(2))) , v = sqrt(2aS) , sin theta = h/s `