A solid cylinder starts rolling down on an inclined plane from its top and `V` is velocity of its centre of mass on reaching the bottom of inclined plane. If a block starts sliding down on an identical inclined plane but smooth, from its top, then the velocity of block on reaching the bottom of inlined plane is

Options

A. `v/(sqrt(2))`
B. `sqrt(2)v`
C. `sqrt(3/2)`
D. `sqrt(2/3)`v

Answer

C

Explanation

For cylinder , ` v_(1) = sqrt((2gh)/(1+(k^(2))/(R^(2)))) = v ` For block `v_(2) = sqrt(2gh)`