Two rotating bodies `A` and `B` of masses `m` and `2m` with moments of inertia `I_(A)` and `I_(B) (I_(B) gt I_(A))` have equal kinetic energy of rotation. If `L_(A)` and `L_(B)` be their angular momenta respectively, then

Options

A. `L_(B) gtL_(A)`
B. `L_(A) gtL_(B)`
C. `L_(A) = (L_(B))/2`
D. `L_(A)=2L_(B)`

Answer

A

Explanation

`K_(A)=K_(B)rArr (L_(A)^(2))/(2I_(A))=(L_(B)^(2))/(2I_(B))`
` :. I_(B) gt I_(A) :. L_(A)^(2) lt L_(B)^(2) rArr L_(A) lt L_(B)`