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A circular ring of mass 6kg and radius a...

A circular ring of mass 6kg and radius a is placed such that its center of lies at the origin. Two particles of masses 2 kg each are placed at the intersecting points of the circle with positive X-axis and positive Y-axis. Then, the angle made by the position vector of center of mass of entire system with X-axis is

A

`45^(@`

B

`60^(@)`

C

`tan^(-1)(4//5)`

D

`30^(@)`

Text Solution

Verified by Experts

The correct Answer is:
A

`tan theta = (y_(cm))/(x_(cm))`
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