The figure shows the positions and ve...

The figure shows the positions and velocities of two particles . If the particles move under the mutual attraction of each other , then the position of centre of mass at t = 1 s is

x = 5 m

x = 6 m

x = 3m

x = 2m

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The correct Answer is:

`x_(cm) = (x_(1)+x_(2))/2`

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