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A wheel is rotating about an axis th...

A wheel is rotating about an axis through its centre at 720 rpm . It is acted on by a constant torque opposing its motion for 8 seconds to bring it to rest finally . The value of torque ( in N-m ) Is :- (Given `I = (24)/pi kg - m^(2)`)

A

48

B

72

C

96

D

120

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The correct Answer is:
To solve the problem step by step, we will follow the given information and apply the relevant physics concepts. ### Step 1: Convert Angular Velocity from RPM to Radians per Second The initial angular velocity (ω_i) is given as 720 revolutions per minute (rpm). To convert this to radians per second, we use the conversion factor: \[ \text{1 revolution} = 2\pi \text{ radians} \] \[ \text{1 minute} = 60 \text{ seconds} \] Thus, we can convert 720 rpm to radians per second: \[ \omega_i = 720 \, \text{rpm} \times \frac{2\pi \, \text{radians}}{1 \, \text{revolution}} \times \frac{1 \, \text{minute}}{60 \, \text{seconds}} = 720 \times \frac{2\pi}{60} \] Calculating this gives: \[ \omega_i = 720 \times \frac{2\pi}{60} = 720 \times \frac{1}{30} \times 2\pi = 24\pi \, \text{radians/second} \] ### Step 2: Identify Final Angular Velocity The final angular velocity (ω_f) when the wheel comes to rest is: \[ \omega_f = 0 \, \text{radians/second} \] ### Step 3: Use the Angular Motion Equation We can use the angular motion equation: \[ \omega_f = \omega_i + \alpha t \] Where: - \( \alpha \) is the angular acceleration, - \( t \) is the time duration (8 seconds). Substituting the known values: \[ 0 = 24\pi + \alpha \cdot 8 \] Rearranging to find α: \[ \alpha \cdot 8 = -24\pi \] \[ \alpha = -\frac{24\pi}{8} = -3\pi \, \text{radians/second}^2 \] ### Step 4: Calculate Torque The torque (τ) can be calculated using the formula: \[ \tau = I \cdot \alpha \] Where: - \( I \) is the moment of inertia, given as \( \frac{24}{\pi} \, \text{kg m}^2 \). Substituting the values: \[ \tau = \left(\frac{24}{\pi}\right) \cdot (-3\pi) \] Simplifying this: \[ \tau = -\frac{24 \cdot 3\pi}{\pi} = -72 \, \text{N-m} \] Since we are interested in the magnitude of torque, we take the positive value: \[ \tau = 72 \, \text{N-m} \] ### Final Answer The value of the torque is \( 72 \, \text{N-m} \). ---

To solve the problem step by step, we will follow the given information and apply the relevant physics concepts. ### Step 1: Convert Angular Velocity from RPM to Radians per Second The initial angular velocity (ω_i) is given as 720 revolutions per minute (rpm). To convert this to radians per second, we use the conversion factor: \[ \text{1 revolution} = 2\pi \text{ radians} \] \[ ...
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NARAYNA-SYSTEM OF PARTICLES AND ROTATIONAL MOTION -EXERCISE - IV
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