A particle of mass m describes a circle ...

A particle of mass `m` describes a circle of radius `r` . The centripetal acceleration of the particle is `(4)/(r^(2))` . What will be the momentum of the particle ?

2m/r

`2m//sqrt(r )`

`4m//sqrt(r )`

4m/r

Text Solution

Verified by Experts

The correct Answer is:

`a = (v^(2))/r rArr v^(2) = ar rArr v = sqrt(ar) = p = mv`

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