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A particle moves in a circular path of r...

A particle moves in a circular path of radius R with an angular velocity `omega=a-bt`, where a and b are positive constants and t is time. The magnitude of the acceleration of the particle after time `(2a)/(b)` is

A

a/R

B

`a^(2)R`

C

`R(a^(2)+b)`

D

`Rsqrt(a^(4)+b^(2))`

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The correct Answer is:
D
Find `X_(cm) & Y_(cm) , bar(r )_(cm) = X_(cm) hat(i) + Y_(cm) hat(j)`
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