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In a horizontal pipe line of uniform cro...

In a horizontal pipe line of uniform cross-section, pressure falls by 5 Pa between two points separated by 1 km. The change in the kinetic energy per kg of the oil flowing at these points is (density of oil `=800kgm^(-3))`

A

`6.25xx10^(-3)Jkg^(-1)`

B

`5.25xx10^(-4)Jkg^(-1)`

C

`3.25xx10^(-5)Jkg^(-1)`

D

`4.25xx10^(-2)Jkg^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`(P_(1)-P_(2))/(rho)=(1)/(2)(V_(2)^(2)-V_(1)^(2))`
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