A drop of water of radius 0.0015 mm is falling in air .If the cofficient of viscosity of air is `2.0 xx 10^(-5) kg m^(-1)s^(-1)` ,the terminal velocity of the drop will be
(The density of water = `10^(3) kg m^(-3)` and g = `10 m s^(-2)` )

Options

A. `1.0 xx10^(-4) m//s`
B. `2.0 xx10^(-4) m//s`
C. `2.5 xx10^(-4) m//s`
D. `5.0 xx10^(-4) m//s`

Answer

C

Explanation

`V_(T)=(2)/(9)(r^(2))/(eta)(rho-sigma)g`