The cylindrical tube of a spray pump has radius `R`, one end of which has `n` fine holes, each of radius `r`. If the speed of the liquid in the tube is `V`, the speed of the ejection of the liquid through the holes is:

Options

A. `(V^(2)R)/(nr)`
B. `(VR^(2))/(n^(2)r^(2))`
C. `(VR^(2))/(nr^(2))`
D. `(VR^(2))/(n^(3)r^(2))`

Answer

C

Explanation

`A_(1)xxV_(1)=A_(2)xxV_(2)`