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A simple harmonic wave has the equation ...

A simple harmonic wave has the equation `y=3.5sin(314t-1.57x)` where time is measured in second, `x` in metre and `y` in c.m. Calculate
`(a)` Frequency
`(b)` Wavelength of the wave
Another wave has the equation `y=0.1sin(314t-1.57x+1.57)`
Calculate the phase difference between this wave and the wave represented by the earlier wave equation.

Text Solution

Verified by Experts

`y=3.5sin(314t-1.57x)implies` comparing this with `y=Asin(2pint-(2pix)/(lambda))`
`2pin=314impliesn=50Hz`, `(2pi)/(lambda)=1.57implieslambda=4cm`
Phase difference between the waves
`Deltaphi=theta_(1)~theta_(2)=(314t-1.57x+1.57)`
`-(314t-1.57x)=1.57=(pi)/(2)` rad
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NARAYNA-WAVES-Exercise-IV
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