The transverse displacement of a string clamped at its both ends is given by
`y(x, t) = 0.06 sin ((2pi)/3 x) cos(l20pit)` where x and y are in m and t in s. The length of the string is 1.5 m and its mass is `3 xx 10^(-2)` kg. The tension in the string is

Explanation

`y=0.06sin((2pi)/(3)x)cos120pit`
The above equation of wave represents a standing wave.
Comparing with standard equation of standing wave,
`y=Asin.(2pi)/(lambda)xcos.(2pi)/(lambda).vt` we have `A=0.06m`,
`(2pi)/(lambda)=(2pi)/(3)implieslambda=3m`
`(2pi)/(lambda).v=120piimpliesv=lambdaxx60=3xx60`, `v=180m//s`
Let tension in the string be `T=impliesv=sqrt((T)/(m))`
`T=v^(2).m=(180)^(2)xx(3.0xx10^(-2))/(1.5)` {`m=` mass per unit length `=(3.0xx10^(-2))/(1.5)`} `impliesT=648N`