Standing waves are producedin a rubber tube `12m` long . If the tube vibrates in five segmens and the velocity of the wave is `480m//s`, what is `(a)` the wave length of the waves `(b)` the frequency of the wave ?

Explanation

To solve the problem step by step, we will first determine the wavelength of the standing waves in the rubber tube and then calculate the frequency of the wave.

### Step 1: Understand the relationship between segments and wavelength
In a standing wave, the number of segments (or loops) is related to the wavelength. Each segment corresponds to half a wavelength (λ/2).

Given that the tube vibrates in 5 segments, we can express the total length of the tube in terms of the wavelength:
\[
\text{Length of the tube} = \text{Number of segments} \times \frac{\lambda}{2}
...