Two coherent sources are at distances `x_(1)=0.2m` and `x_(2)=0.08m` from a point. Consider the intensity of resultant wave at that point if the frequency of each wave is `f=400Hz` and velocity of wave in the medium is `V=192m//s`
The intensity of each wave is `I_(0)=60W//m^(2)`

Explanation

To solve the problem, we need to find the resultant intensity of the waves from two coherent sources at given distances from a point. Here’s a step-by-step solution:

### Step 1: Calculate the Path Difference
The path difference (Δx) between the two waves is given by the difference in distances from the sources to the point.

\[ \Delta x = x_1 - x_2 = 0.2 \, \text{m} - 0.08 \, \text{m} = 0.12 \, \text{m} \]
...