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The slope of a transversely vibrating st...

The slope of a transversely vibrating string at any point on it is numerically equal to

A

The ratio of the particle speed at that point to the wave speed in the string

B

The ratio of the wave speed in the string to the particle speed at that point

C

One

D

Zero

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AI Generated Solution

The correct Answer is:
To find the numerical value of the slope of a transversely vibrating string at any point on it, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Motion of the String**: - A transversely vibrating string means that the particles of the string move perpendicular to the direction of the wave propagation. 2. **Assume the Wave Equation**: - We can represent the displacement of the string as a function of position \( x \) and time \( t \) using the wave equation: \[ y(x, t) = A \sin(\omega t - kx) \] - Here, \( A \) is the amplitude, \( \omega \) is the angular frequency, and \( k \) is the wave number. 3. **Calculate the Slope**: - The slope of the string at any point is given by the partial derivative of \( y \) with respect to \( x \): \[ \frac{dy}{dx} = \frac{d}{dx}(A \sin(\omega t - kx)) \] - Using the chain rule, we differentiate: \[ \frac{dy}{dx} = A \cos(\omega t - kx) \cdot (-k) = -Ak \cos(\omega t - kx) \] 4. **Calculate the Velocity of the Particles**: - The velocity of the particles of the string is given by the partial derivative of \( y \) with respect to \( t \): \[ \frac{dy}{dt} = \frac{d}{dt}(A \sin(\omega t - kx)) = A \omega \cos(\omega t - kx) \] 5. **Relate Slope to Particle and Wave Velocity**: - The ratio of the slope to the velocity of the particle can be expressed as: \[ \frac{\frac{dy}{dx}}{\frac{dy}{dt}} = \frac{-Ak \cos(\omega t - kx)}{A \omega \cos(\omega t - kx)} \] - Simplifying this gives: \[ \frac{dy}{dx} = -\frac{k}{\omega} \cdot \frac{dy}{dt} \] - Since \( \frac{v}{\omega} = \frac{1}{k} \) (where \( v \) is the wave speed), we can express this as: \[ \frac{dy}{dx} = -\frac{1}{v} \cdot \frac{dy}{dt} \] 6. **Final Expression**: - The magnitude of the slope is therefore given by: \[ |\text{slope}| = \frac{|\text{velocity of particle}|}{|\text{velocity of wave}|} \] ### Conclusion: The slope of a transversely vibrating string at any point is numerically equal to the ratio of the velocity of the particle at that point to the velocity of the wave in the string.
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