Two simple harmonic are represented by the equation `y_(1)=0.1 sin (100pi+(pi)/3) and y_(2)=0.1 cos pit`.
The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is.

Options

A. `-(pi)/(6)`
B. `(pi)/(3)`
C. `-(pi)/(3)`
D. `(pi)/(6)`

Answer

A

Explanation

`V_(1)=(dy_(1))/(dt)=10pisin[100pit+(pi)/(3)+(pi)/(2)]`
`V_(2)=(dy_(2))/(dt)=0.1pisin[pit+pi]`
`Deltatheta=theta_(1)-theta_(2)=(100pit+(pi)/(3)+(pi)/(2))-(pit+pi)`
Put `t=0` to get the answer