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A transverse wave is passing through a l...

A transverse wave is passing through a light string shown in fig.The equation of wave is `y=A sin(wt-kx)` the area of cross-section of string `A` and density is `rho` the hanging mass is

A

`Aomega`

B

`(omega)/(kg)`

C

`(rhoAomega^(2))/(k^(2)g)`

D

`(k^(2)g)/(omega)`

Text Solution

Verified by Experts

The correct Answer is:
C
`V^(2)=(Mg)/(Arho)`, `(omega^(2))/(K^(2))=(Mg)/(Arho)`
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