In (Q. 24.) the tension in string is T and the linear mass density of string is `mu`. The ratio of magnitude of maximum velocity of particle and the magnitude of maximum acceleration is

Options

A. `(1)/(2pi)sqrt(((mul^(2))/(T)))`
B. `2pisqrt(((mul^(2))/(T)))`
C. `(1)/(2pi)sqrt(((T)/(mul^(2))))`
D. `(1)/(4pi)sqrt(((mul^(2))/(T)))`

Answer

A

Explanation

`((V_(rho))_(max))/((a_(rho))_(max))=(Aomega)/(Aomega^(2))=(1)/(omega)=(1)/(kv)=(lambda)/(2pi)sqrt((mu)/(T))`
here `lambda=l` for `2`nd harmonic