The temperature at which the velocity of sound in oxygen will be same as that of nitrogen at `15^(@) C` is

Options

A. `561^(@)C`
B. `56.1^(@)C`
C. `5.61^(@)C`
D. `5.061^(@)C`

Answer

B

Explanation

`V=sqrt((gammaRT)/(M))implies(T)/(M)=` constant for same speed and both are diatomic `implies(T_(1))/(T_(2))=(M_(1))/(M_(2))`