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An observer moves towards a stationary source of sound, with a velocity one-fifth of the velocity of sound. What is the percentage increase in the apparent frequency?

A

`5%`

B

`20%`

C

zero

D

`0.5%`

Text Solution

Verified by Experts

The correct Answer is:
B
`n.=m[(v+v_(0))/(v)]` and Percentage increase `(n.-n)/(n)xx100%=(nv_(0))/(v)xx100%`
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