The equation of a progressive wave is `y=0.05sin(200t-(x)/(2))` where x,y are in metres and t in seconds then
`(a)` velocity of wave is `100ms^(-1)`
`(b)` max velocity of particle is `10ms^(-1)`
`(c )` wavelength of wave is `4m`

Options

A. only a and c are true
B. only b and c are true
C. only a and b are true
D. a,b,c are true

Answer

B

Explanation

By comparing with `y=Asin(omegat-kx)` we get
`omega=200rad//sec`, `K=(1)/(2)m^(-1),A-0.05m`
`(a) V=(omega)/(K) (b) (V_(rho))_(max)=Aomega`
`(c ) lambda=(2pi)/(K)`