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A stretched wire of length 114cm is divi...

A stretched wire of length `114cm` is divided into three segments whose frequencies are in the ratio `1 : 3 : 4`, the lengths of the segments must be in the ratio :

A

`18:24:72`

B

`24:72:18`

C

`24:18:72`

D

`72:24:18`

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The correct Answer is:
To solve the problem of finding the lengths of the segments of a stretched wire divided into three parts with frequencies in the ratio of 1:3:4, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Relationship Between Frequency and Length**: The frequency of a vibrating string is inversely proportional to its length. This means that if the frequencies are in the ratio \( \nu_1 : \nu_2 : \nu_3 = 1 : 3 : 4 \), then the lengths will be in the inverse ratio: \[ \frac{L_1}{L_2} = \frac{\nu_2}{\nu_1} = \frac{3}{1} \quad \text{and} \quad \frac{L_2}{L_3} = \frac{\nu_3}{\nu_2} = \frac{4}{3} \] 2. **Express Lengths in Terms of a Common Variable**: Let the lengths of the segments be \( L_1, L_2, \) and \( L_3 \). From the ratios: \[ L_2 = 3L_1 \quad \text{and} \quad L_3 = \frac{3}{4}L_2 = \frac{3}{4}(3L_1) = \frac{9}{4}L_1 \] 3. **Set Up the Equation for Total Length**: The total length of the wire is given as 114 cm: \[ L_1 + L_2 + L_3 = 114 \] Substituting the expressions for \( L_2 \) and \( L_3 \): \[ L_1 + 3L_1 + \frac{9}{4}L_1 = 114 \] 4. **Combine the Terms**: Combine the terms on the left side: \[ L_1 + 3L_1 + \frac{9}{4}L_1 = \left(1 + 3 + \frac{9}{4}\right)L_1 = \left(\frac{4}{4} + \frac{12}{4} + \frac{9}{4}\right)L_1 = \frac{25}{4}L_1 \] Thus, we have: \[ \frac{25}{4}L_1 = 114 \] 5. **Solve for \( L_1 \)**: Multiply both sides by \( \frac{4}{25} \): \[ L_1 = 114 \cdot \frac{4}{25} = \frac{456}{25} = 18.24 \text{ cm} \] 6. **Calculate \( L_2 \) and \( L_3 \)**: Now, substituting \( L_1 \) back to find \( L_2 \) and \( L_3 \): \[ L_2 = 3L_1 = 3 \cdot 18.24 = 54.72 \text{ cm} \] \[ L_3 = \frac{9}{4}L_1 = \frac{9}{4} \cdot 18.24 = 40.56 \text{ cm} \] 7. **Find the Ratios**: Now we can express the lengths in their simplest ratio form: \[ L_1 : L_2 : L_3 = 18.24 : 54.72 : 40.56 \] Dividing each length by \( 18.24 \): \[ 1 : 3 : 2.22 \approx 1 : 3 : 2.2 \] ### Final Answer: The lengths of the segments must be in the ratio \( 1 : 3 : 4 \).

To solve the problem of finding the lengths of the segments of a stretched wire divided into three parts with frequencies in the ratio of 1:3:4, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Relationship Between Frequency and Length**: The frequency of a vibrating string is inversely proportional to its length. This means that if the frequencies are in the ratio \( \nu_1 : \nu_2 : \nu_3 = 1 : 3 : 4 \), then the lengths will be in the inverse ratio: \[ \frac{L_1}{L_2} = \frac{\nu_2}{\nu_1} = \frac{3}{1} \quad \text{and} \quad \frac{L_2}{L_3} = \frac{\nu_3}{\nu_2} = \frac{4}{3} ...
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