Home
Class 11
PHYSICS
Transverse waves are produced in a stret...

Transverse waves are produced in a stretched wire. Both ends of the string are fixed. Let us compare between second overtone mode (in numerator) and fifth harmonic, mode (in denominator).
match the following column-I with column-II

A

`a-r,b-p,c-r,d-s`

B

`a-q,b-p,c-s,d-s`

C

`a-r,b-s,c-q,d-p`

D

`a-s,b-p,c-r,d-p`

Text Solution

Verified by Experts

The correct Answer is:
A

In second overtone number of antinodes is `3`, nodes is `4` and in fifth harmonic number of antinodes is `5` and nodes is `6`.
Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

A string fixed at both ends first oscillates in its fundamental mode then in second harmonic mode.Then match the following.

A transverse wave is produced on a stretched string 0.9 m long and fixed at its ends. Find the speed of the transverse wave, when the string vibrates while emitting second overtone of frequency 324 Hz.

Stationary wave of frequency 5 K Hz is produced in a tube open at both ends and filled with air at 300 K . The tube is oscillating in its first overtone mode. (a) Find the length of the tube assuming that air contains only nitrogen and oxygen in molar ratio of 3 : 1 . (b) What shall be the frequency of sound wave used so that the same tube oscillates in its second overtone mode?

A wire is stretched and fixed at two ends. Transverse stationary waves are formed in it. It oscillates in its third overtone mode. The equation of stationary wave is y= A sin kx cos omegat Choose the correct options.

Stationary waves are produced in a length of wire fixed between two points . Compare the amplitudes at an antinode for the fundamental and the first overtone . Assume that the total energy of the initial waves is , on an average , equally divided between the two modes.

Assertion: A wire is stretched and then fixed at two ends. It oscillates in its second overtone mode. There are total four nodes and three antinodes. Reason: In second overtone mode, length of wire should be l=(3lambda)/2 , where lambda is wavelength.

A stretched wire is oscillating in third overtone mode. Equation of transverse stationary wave produced in this wire is y= A sin (6pix)sin(20pit) Here, x is in metres. Find the length of the wire.

The frequency of fundamental mode of vibration of a stretched string fixed at both the ends is 25 Hz. If the string is made to vibrate with 7 nodes , what is the frequency of vibration ? If the length of string is 3 m , what is the frequency of the 4th harmonic ?