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The equation of a wave travelling on a s...

The equation of a wave travelling on a string is `y=4sin[(pi)/(2)(8t-(x)/(8))]`, where `x,y` are in cm and t in second. They velocity of the wave is

A

`64cms^(-1)` in `-x` direction

B

`32cms^(-1)` in `-x` direction

C

`32cms^(-1)` in `+x` direction

D

`64cms^(-1)` in `+x` direction

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To find the velocity of the wave described by the equation \( y = 4 \sin\left(\frac{\pi}{2}(8t - \frac{x}{8})\right) \), we will follow these steps: ### Step 1: Identify the angular frequency (\( \omega \)) and the wave number (\( k \)) The general form of a wave equation is given by: \[ y = A \sin(\omega t - kx) \] From the given equation, we can identify: - \( \omega t = \frac{\pi}{2} \cdot 8t \) implies \( \omega = 4\pi \) - \( kx = \frac{\pi}{2} \cdot \frac{x}{8} \) implies \( k = \frac{\pi}{16} \) ### Step 2: Use the relationship between velocity, angular frequency, and wave number The velocity \( v \) of the wave can be calculated using the formula: \[ v = \frac{\omega}{k} \] ### Step 3: Substitute the values of \( \omega \) and \( k \) Now substituting the values we found: \[ v = \frac{4\pi}{\frac{\pi}{16}} \] ### Step 4: Simplify the expression To simplify this, we can multiply by the reciprocal of \( k \): \[ v = 4\pi \cdot \frac{16}{\pi} = 64 \] ### Step 5: State the final answer with units Since \( x \) and \( y \) are in centimeters and \( t \) is in seconds, the velocity will be in centimeters per second: \[ v = 64 \, \text{cm/s} \] ### Final Answer The velocity of the wave is \( 64 \, \text{cm/s} \). ---

To find the velocity of the wave described by the equation \( y = 4 \sin\left(\frac{\pi}{2}(8t - \frac{x}{8})\right) \), we will follow these steps: ### Step 1: Identify the angular frequency (\( \omega \)) and the wave number (\( k \)) The general form of a wave equation is given by: \[ y = A \sin(\omega t - kx) ...
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