The wave decribed by `y=0.25sin(10pix-2pit)`. Where x and y are in metre and t is second, is a wave travelling along the Therefore, the wave is travelling along `+ve` x direction with frequency `1 Hz `and wavelength `0.2m`

Options

A. `-` ve x direction with frequency `1Hz`
B. `+` ve x direction with frequency `piHz` and wavelength `lambda=0.2m`
C. `+` ve x direction with frequency `1Hz` and wavelength `lambda=0.2m`
D. `-` ve x direction with amplitude `0.2m` and wavelength `lambda=0.2m`

Answer

C

Explanation

`y=0.25sin(10pix-2pit)`…………`(i)`
The minus `(-)` between `(10pix)` and `(2pit)` implies that the wave is travelling along positive x direction. `a=0.25m`, `omega=2pi`, `k=10pim`
`omega=2pifimpliesf=1`Also, `lambda=(2pi)/(k)=(2pi)/(10pi)=0.2m`