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Each of the two strings of length 51.6 c...

Each of the two strings of length `51.6 cm` and `49.1 cm` are tensioned separately by `20 N` force. Mass per unit length of both the strings is same and equal to `1 g//m`. When both the strings vibrate simultaneously, the number of beats is

A

`7`

B

`8`

C

`3`

D

`5`

Text Solution

Verified by Experts

The correct Answer is:
A
Beats /sec `=n_(1).n_(2)=(1)/(2l_(1))sqrt((T)/(mu))-(1)/(2l_(2))sqrt((T)/(mu))`
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