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A fork A has frequency 2% more than the ...

A fork A has frequency `2%` more than the standard fork and B has a frequency `3%` less than the frequency of same standard frok. The forks A and B when sounded together produced 6 beats/s. The frequency of fork A is

A

`116.4Hz`

B

`120Hz`

C

`122.4Hz`

D

`238.8Hz`

Text Solution

Verified by Experts

The correct Answer is:
C
`n_(A)=n+(2)/(100)n`, `n_(B)=n-(3)/(100)n`, `n_(A)-n_(B)=6`
`((5)/(100)n)=6` gives `n=(600)/(5)=120Hz`
Substituting `n` in `n_(A)-n_(B)=6` we get A and B
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