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The equation of a wave is y=5sin((t)/(0....

The equation of a wave is `y=5sin((t)/(0.04)-(x)/(4))` where `x` is in cm and t is in seccond. The velocity of the wave will be

A

`1ms^(-1)`

B

`2ms^(-1)`

C

`1.5ms^(-1)`

D

`1.25ms^(-1)`

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The correct Answer is:
To find the velocity of the wave given by the equation \( y = 5 \sin\left(\frac{t}{0.04} - \frac{x}{4}\right) \), we will follow these steps: ### Step 1: Identify the wave equation format The general form of a wave equation is: \[ y = A \sin(\omega t - kx) \] where: - \( A \) is the amplitude, - \( \omega \) is the angular frequency, - \( k \) is the wave number. ### Step 2: Compare the given equation with the general form From the given equation: \[ y = 5 \sin\left(\frac{t}{0.04} - \frac{x}{4}\right) \] we can identify: - \( \omega = \frac{1}{0.04} \) - \( k = \frac{1}{4} \) ### Step 3: Calculate the values of \( \omega \) and \( k \) Calculating \( \omega \): \[ \omega = \frac{1}{0.04} = 25 \, \text{rad/s} \] Calculating \( k \): \[ k = \frac{1}{4} \, \text{rad/cm} \] ### Step 4: Use the relationship between \( \omega \), \( k \), and wave velocity \( v \) The relationship is given by: \[ v = \frac{\omega}{k} \] ### Step 5: Substitute the values of \( \omega \) and \( k \) Substituting the values: \[ v = \frac{25}{\frac{1}{4}} = 25 \times 4 = 100 \, \text{cm/s} \] ### Step 6: Convert the velocity to meters per second Since the question asks for the velocity in meters per second, we convert: \[ 100 \, \text{cm/s} = 1 \, \text{m/s} \] ### Final Answer The velocity of the wave is: \[ \boxed{1 \, \text{m/s}} \] ---

To find the velocity of the wave given by the equation \( y = 5 \sin\left(\frac{t}{0.04} - \frac{x}{4}\right) \), we will follow these steps: ### Step 1: Identify the wave equation format The general form of a wave equation is: \[ y = A \sin(\omega t - kx) \] where: ...
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