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A uniform rope of legnth L and mass m1 h...

A uniform rope of legnth `L` and mass `m_1` hangs vertically from a rigid support. A block of mass `m_2` is attached to the free end of the rope. A transverse pulse of wavelength `lamda_1` is produced at the lower end of the rope. The wavelength of the pulse when it reaches the top of the rope is `lamda_2`. The ratio `(lamda_2)/(lamda_1)` is

A

`sqrt((m_(1)+m_(2))/(m_(1)))`

B

`sqrt((m_(1))/(m_(2)))`

C

`sqrt((m_(1)+m_(2))/(m_(2)))`

D

`sqrt((m_(2))/(m_(1)))`

Text Solution

Verified by Experts

The correct Answer is:
C

`(lambda_(2))/(lambda_(1))=(V_(2))/(V_(1))=sqrt((m_(1)+m_(2))/(m_(2)))`
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