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The magnetic field in a certain region i...

The magnetic field in a certain region is given by
`vecB=(4hati-hatk)` tesla. How much magnetic flux passes through the loop of area 100.0cm2 lies flat in xy plane ?

A

`-0.01 `

B

`-0.02`

C

`-0.03`

D

`-0.04`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the magnetic flux through a loop in the xy-plane with a given magnetic field, we can follow these steps: ### Step 1: Understand the magnetic field and area vector The magnetic field is given as: \[ \vec{B} = (4\hat{i} - 4\hat{k}) \, \text{T} \] The area of the loop is given as \(100.0 \, \text{cm}^2\). First, we need to convert this area into square meters: \[ 100.0 \, \text{cm}^2 = 100.0 \times 10^{-4} \, \text{m}^2 = 0.01 \, \text{m}^2 \] Since the loop lies flat in the xy-plane, the area vector \(\vec{A}\) will be perpendicular to the surface of the loop, which points in the positive z-direction. Therefore, the area vector can be expressed as: \[ \vec{A} = 0.01 \hat{k} \, \text{m}^2 \] ### Step 2: Calculate the magnetic flux The magnetic flux \(\Phi\) through the loop is given by the dot product of the magnetic field vector \(\vec{B}\) and the area vector \(\vec{A}\): \[ \Phi = \vec{B} \cdot \vec{A} \] Substituting the values we have: \[ \Phi = (4\hat{i} - 4\hat{k}) \cdot (0.01 \hat{k}) \] ### Step 3: Perform the dot product The dot product can be computed as follows: \[ \Phi = 4\hat{i} \cdot (0.01 \hat{k}) + (-4\hat{k}) \cdot (0.01 \hat{k}) \] Since \(\hat{i} \cdot \hat{k} = 0\) (they are perpendicular), the first term becomes zero: \[ \Phi = 0 + (-4)(0.01) = -0.04 \, \text{Wb} \] ### Step 4: Final answer Thus, the magnetic flux passing through the loop is: \[ \Phi = -0.04 \, \text{Wb} \]

To solve the problem of finding the magnetic flux through a loop in the xy-plane with a given magnetic field, we can follow these steps: ### Step 1: Understand the magnetic field and area vector The magnetic field is given as: \[ \vec{B} = (4\hat{i} - 4\hat{k}) \, \text{T} \] The area of the loop is given as \(100.0 \, \text{cm}^2\). First, we need to convert this area into square meters: ...
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NARAYNA-ELECTROMAGNETIC INDUCTION-EXERCISE-1 (C.W)
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  2. The magnetic field perpendicular to the plane of a loop of area 0.1 m ...

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  3. The magnetic field in a certain region is given by vecB=(4hati-hatk)...

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  4. A coil and a magnet moves with their constant speeds 10 m/sec and 5 m/...

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  5. The radius of a circular coil having 100 turns is 2 cm. its plane is n...

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  6. A short magnet is allowed to fall along the axis of a horizontal metal...

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  7. Magnetic flux in a circuite containing a coil of resistance 2Omegachan...

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  8. A coil of self inductance 2H carries a 2A current If direction of curr...

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  9. In an inductor of self-inductance L=2 mH, current changes with time ac...

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  10. A Conducting ring of radius 1 meter is placed in an uniform magnetic f...

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  11. when the wire loop is rotated in the magnetic field between the poles...

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  12. An inductor of 2 henry and a resistance of 10 ohms are connected in se...

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  13. A solenoid is 1.5 m long and its inner diameter is 4.0 cm . It has thr...

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  14. The current in ampere in an inductor is given by I=5 +16 t where t is...

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  15. The magnetic flux linked with a coil, in webers is given by the equati...

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  16. In a magnetic field of 0.05T, area of a coil changes from 101 cm^(2) t...

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  17. The magnetic flux phi (in weber ) in a closed circuit of resistance 10...

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  18. A field of strenght 5 xx 10^(4)//pi ampere turns//meter acts at right ...

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  19. A coil has 1,000 turns and 500 cm^(2) as its area. The plane of the co...

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  20. A square loop of side 22 cm is changed to a circle in time 0.4 sec wit...

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