The magnetic field perpendicular to the plane of a loop of area `0.5 m^2` is 0.6 T . Calculate the magnetic flux through the loop (in weber)

Options

A. 0.1
B. 0.2
C. 0.3
D. 0.4

Explanation

To calculate the magnetic flux through a loop when the magnetic field is perpendicular to the plane of the loop, we can use the formula for magnetic flux (Φ):

\[ Φ = B \cdot A \cdot \cos(θ) \]

Where:
- \(Φ\) is the magnetic flux in webers (Wb),
- \(B\) is the magnetic field in teslas (T),
- \(A\) is the area of the loop in square meters (m²),
- \(θ\) is the angle between the magnetic field and the normal (perpendicular) to the surface of the loop.

### Step-by-Step Solution:

1. **Identify the given values**:
- Area of the loop, \(A = 0.5 \, m^2\)
- Magnetic field, \(B = 0.6 \, T\)
- Since the magnetic field is perpendicular to the plane of the loop, the angle \(θ = 0°\).

2. **Calculate the cosine of the angle**:
- \(\cos(0°) = 1\)

3. **Substitute the values into the magnetic flux formula**:
\[ Φ = B \cdot A \cdot \cos(θ) = 0.6 \, T \cdot 0.5 \, m^2 \cdot 1 \]

4. **Perform the multiplication**:
\[ Φ = 0.6 \cdot 0.5 = 0.3 \, Wb \]

5. **Conclusion**:
- The magnetic flux through the loop is \(0.3 \, Wb\).

### Final Answer:
The magnetic flux through the loop is \(0.3 \, Wb\).

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