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A coil and a magnet moves with their con...

A coil and a magnet moves with their constant speeds 6 m/sec and 2 m/sec respectively, towards each other, then induced emf in coil is 18 mV. If both are move in same direction , then induced emf in coil

A

5 mV

B

7 mV

C

3 mV

D

9 mV

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The correct Answer is:
To solve the problem, we need to analyze the situation using the principles of electromagnetic induction, particularly focusing on the concept of relative velocity between the coil and the magnet. ### Step-by-Step Solution: 1. **Identify the Given Information:** - Speed of the coil (V_coil) = 6 m/s - Speed of the magnet (V_magnet) = 2 m/s - Induced EMF when moving towards each other (E) = 18 mV 2. **Calculate the Relative Velocity When Moving Towards Each Other:** - When the coil and magnet move towards each other, their relative velocity (V_rel) is the sum of their speeds: \[ V_{rel} = V_{coil} + V_{magnet} = 6 \, \text{m/s} + 2 \, \text{m/s} = 8 \, \text{m/s} \] 3. **Understanding the Induced EMF:** - According to Faraday's law of electromagnetic induction, the induced EMF (E) is directly proportional to the relative velocity: \[ E \propto V_{rel} \] 4. **Calculate the Relative Velocity When Moving in the Same Direction:** - When both the coil and the magnet move in the same direction, the relative velocity is the difference of their speeds: \[ V_{rel}' = V_{coil} - V_{magnet} = 6 \, \text{m/s} - 2 \, \text{m/s} = 4 \, \text{m/s} \] 5. **Set Up the Proportionality for Induced EMF:** - Let E' be the induced EMF when both are moving in the same direction. Using the proportionality: \[ \frac{E'}{E} = \frac{V_{rel}'}{V_{rel}} \] - Substitute the known values: \[ \frac{E'}{18 \, \text{mV}} = \frac{4 \, \text{m/s}}{8 \, \text{m/s}} \] 6. **Solve for E':** - Cross-multiply to find E': \[ E' = 18 \, \text{mV} \times \frac{4}{8} = 18 \, \text{mV} \times \frac{1}{2} = 9 \, \text{mV} \] 7. **Conclusion:** - The induced EMF in the coil when both the coil and the magnet are moving in the same direction is **9 mV**.

To solve the problem, we need to analyze the situation using the principles of electromagnetic induction, particularly focusing on the concept of relative velocity between the coil and the magnet. ### Step-by-Step Solution: 1. **Identify the Given Information:** - Speed of the coil (V_coil) = 6 m/s - Speed of the magnet (V_magnet) = 2 m/s - Induced EMF when moving towards each other (E) = 18 mV ...
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NARAYNA-ELECTROMAGNETIC INDUCTION-EXERCISE-1 (H.W)
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  3. A coil and a magnet moves with their constant speeds 6 m/sec and 2 m/s...

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  5. A short magnet is allowed to fall along the axis of a horizontal metal...

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  6. Magnetic flux in a circuite containing a coil of resistance 2Omegachan...

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  7. A coil of self inductance 4H carries a 10 A current. If direction of c...

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  8. For a coil having L=4 mH , current flow through it is I=t^3.e^(-t) the...

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  9. A conducting ring of radius 2 metre is placed in an uniform magnetic f...

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  10. When the wire loop is rotated in the magnetic field between the poles...

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  11. An inductor of 5 henry and a resistance of 20 ohm are connected in ser...

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  12. A solenoid is 3 m long and its inner diameter is 4.0 cm . It has three...

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  13. The current in ampere in an inductor is given by I=4t^2+6t where is in...

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  14. The magnetic flux linked with a coil , in Webers, is given by the equa...

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  15. In a magnetic field of 0.08 T, area of a coil changes from 101 cm^2 to...

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  16. The magnetic flux phi (in weber) in a closed circuit of resistance 10 ...

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  17. A field of strength 8 xx 10^4//pi ampere turns / meter acts at right a...

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  18. A coil has 4000 turns and 500 cm^2 as its area. The plane of the coil ...

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  19. A square loop of side 44 cm is changed to a circle in time 0.5 sec wit...

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  20. A coil of 1500 turns and mean area of 500 cm^2 is held perpendicular t...

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