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When the wire loop is rotated in the ma...

When the wire loop is rotated in the magnetic field between the poles of a magnet the frequency of emf is

A

1 revolution

B

2 revolution

C

1/4 revolution

D

1/2 revolution

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The correct Answer is:
To solve the problem of determining the frequency of EMF generated when a wire loop is rotated in a magnetic field, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Setup**: - We have a wire loop rotating in a magnetic field created by a magnet. The magnetic field lines are directed from one pole of the magnet to the other. 2. **Magnetic Flux Calculation**: - The magnetic flux (Φ) through the loop is given by the formula: \[ \Phi = B \cdot A \cdot \cos(\theta) \] where: - \(B\) is the magnetic field strength, - \(A\) is the area of the loop, - \(\theta\) is the angle between the magnetic field and the normal to the surface of the loop. 3. **Induced EMF Calculation**: - According to Faraday's law of electromagnetic induction, the induced EMF (ε) in the loop is given by the rate of change of magnetic flux: \[ \epsilon = -\frac{d\Phi}{dt} = -\frac{d(B \cdot A \cdot \cos(\theta))}{dt} \] - As the loop rotates, \(\theta\) changes, which affects the cosine term. 4. **Analyzing the Rotation**: - When the loop completes one full rotation (360 degrees or \(2\pi\) radians), the angle \(\theta\) changes from 0 to \(2\pi\). - The cosine function oscillates between +1 and -1, meaning the EMF will be positive for half the rotation (0 to \(\pi\)) and negative for the other half (\(\pi\) to \(2\pi\)). 5. **Frequency of EMF**: - Since the EMF changes its sign twice during one complete revolution (once at \(\pi\) and once at \(2\pi\)), the frequency of the EMF can be defined as: \[ \text{Frequency} = \frac{\text{Number of sign changes}}{\text{Time for one revolution}} \] - In one full revolution, the EMF changes sign twice, indicating that the frequency of the EMF is \(1\) cycle per revolution. 6. **Conclusion**: - Therefore, the frequency of the induced EMF when the wire loop is rotated in the magnetic field is: \[ \text{Frequency} = \frac{2}{T} \quad \text{(where T is the time for one complete revolution)} \] - If we consider one complete revolution as one cycle, the frequency of the EMF is \(f = \frac{1}{T}\).

To solve the problem of determining the frequency of EMF generated when a wire loop is rotated in a magnetic field, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Setup**: - We have a wire loop rotating in a magnetic field created by a magnet. The magnetic field lines are directed from one pole of the magnet to the other. 2. **Magnetic Flux Calculation**: ...
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NARAYNA-ELECTROMAGNETIC INDUCTION-EXERCISE-1 (H.W)
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  8. In a magnetic field of 0.08 T, area of a coil changes from 101 cm^2 to...

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  9. The magnetic flux phi (in weber) in a closed circuit of resistance 10 ...

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  10. A field of strength 8 xx 10^4//pi ampere turns / meter acts at right a...

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  11. A coil has 4000 turns and 500 cm^2 as its area. The plane of the coil ...

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  12. A square loop of side 44 cm is changed to a circle in time 0.5 sec wit...

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  13. A coil of 1500 turns and mean area of 500 cm^2 is held perpendicular t...

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  14. A closed coil with a resistance 2R is placed in a magnetic field. The...

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  15. A coil of area 10cm^2 and 10 turns is in magnetic field directed perpe...

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  18. A coil having an area 2m^(2) is placed in a magnetic field which chang...

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  19. A flip coil consits of N turns of circular coils which lie in a unifo...

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