The flux linked with a coil is `0.8 Wb` when a `2` A current is flowing through it. If this current begins to increases at the rate of `400 A//s`, the induced `emf` in the coil will be

Options

A. 20 V
B. 40 V
C. 80 V
D. 160 V

Answer

D

Explanation

`phi=Li rArr L=(0.8)/2=0.4`
`e=L(di)/(dt)=0.4 xx400=160v`