A long solenoid of length L, cross secti...

A long solenoid of length `L`, cross section `A` having `N_(1)` turns has about its center a small coil of `N_(2)` turns as shows in Fig The mutual inductance of two circuits is

`(mu_0A(N_1//N_2))/L`

`(mu_0A(N_1N_2))/L`

`mu_0A(N_1N_2)L`

`(mu_0A(L_1^2N_2))/L`

Text Solution

Verified by Experts

The correct Answer is:

`phi=N_2B-1A or phi_2=N_2(mu_0N_1I_1)/L A or phi_2=(mu_0N_1N_2A)/LI_1`
Comparing with `phi_2=MI_1`, we get
`M_2=(mu_0N_1N_2A)/L`

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