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When photons of energy hv fall on an alu...

When photons of energy `hv` fall on an aluminium plate (of work function `E_(0)`), photoelectrons of maximum kinetic energy `K` are ejected . If the frequency of the radiation is doubled , the maximum kinetic energy of the ejected photoelectrons will be

A

K + hv

B

`K + E_(0)`

C

2 K

D

K

Text Solution

Verified by Experts

The correct Answer is:
1
`E = E_(0)+K`
`K=E-E_(0)+K`
`K=E-E_(0)=hv-E_(0)`
`K.=2E-E_(0)=E+E-E_(0)=K+hv.`
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NARAYNA-DUAL NATURE OF RADIATION AND MATTER-EXERCISE - 2 (C.W)
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