An electron accelerated under a p.d. Of ...

An electron accelerated under a `p.d`. Of `V` volt has a certain wavelength `lambda`. Mass of the proton is `2000` times the mass of an electron. If the proton has to have the same wavelength `lambda`, then it will have to be accelerated under `p.d`. of (volts)

V volt

2000 V volt

`(V)/(2000)` volt

`sqrt(2000) V` volt

Text Solution

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The correct Answer is:

`lambda = (h)/(sqrt(2mqDeltav))`

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