When photons of energy `hv` fall on an aluminium plate (of work function `E_(0)`), photoelectrons of maximum kinetic energy `K` are ejected . If the frequency of the radiation is doubled , the maximum kinetic energy of the ejected photoelectrons will be

Options

A. K + hv
B. `K + E_(0)`
C. `2K
D. K

Answer

1

Explanation

Let K and K. be the maximum kinetic energy of photoelectrons for incident light of frequency v and 2v respectively.
According to Einstein.s photoelectric equation,
`K = hv - E_(0)`
and `K. = h(2v) - E_(0)`
`=2hv - E_(0) = hv + hv - E_(0)`
`K. = hv + k`